Visual Proof: Where the Volume of a Pyramid Formula Actually Comes From
The most intuitive visual proof for the square pyramid begins inside a standard cube. Imagine a cube whose edges each measure length $s$. The volume of this cube is straightforward: $V = s \times s \times s = s^3$.
Now pick an arbitrary interior point inside that cube, specifically, the exact center. If you draw straight lines connecting that center point to each of the cube's eight vertices, you carve the cube into six identical square pyramids. Each pyramid possesses one of the cube's six faces as its base. The apex of all six pyramids converges at the center.
Because the six pyramids completely fill the cube without gaps or overlaps, their volumes must sum to the volume of the cube:
$$6 \times V_{\text{pyramid}} = s^3$$
The perpendicular height ($h$) of each of these six central pyramids is not $s$; it is half the cube's side length, or $\frac{s}{2}$, because the apex sits directly in the center. Expressing the volume of one pyramid in terms of its own base area ($B = s^2$) and its own perpendicular height ($h = \frac{s}{2}$) yields a clean reduction:
$$V_{\text{pyramid}} = \frac{s^3}{6} = \frac{s^2 \times s}{6} = \frac{B \times (2h)}{6} = \frac{2Bh}{6} = \frac{1}{3}Bh$$
Cube dissected into 3 congruent pyramids:
Corner Apex: (0, s, s)
+-----------------------+
-> Base Area = s², Height = s
-> Base Area = s², Height = s
-> Base Area = s², Height = s
+-----------------------+
Total Volume = 3 × ((1/3) × s² × s) = s³
An even simpler dissection avoids fractions entirely. Take that same cube and anchor the apex at one of the top corners. You can cut the cube into three completely congruent, asymmetrical square pyramids. Each pyramid uses one of the three cube faces meeting at the opposite corner as its base, and all three pyramids share the exact same perpendicular height $s$ and base area $s^2$. Three identical pyramids assemble into one cube. Therefore, each pyramid must possess exactly one-third of the total cubic volume.